cs610 assignment 3 solution complete

Question:1

Convert the binary numbers in the decimal dotted notation

10000010  10101000  00001010  00101000 

 [ 130.168.10.40 ] 

(B)  00001010  01111000  00010100  00000000

  [10.120. 20. 0   ]

Question:2

Identify the classes of both IP addresses

  Class B

  Class A

Question: 3

Identify the prefix and suffix parts of both IP addresses

Address class	Bits in prefix	Maximum number of networks	Bits in suffix	Maximum numbers of hosts per network
A	7	128	24	16777216
B	14	16384	16	65536

Question:4

Add “last two digits of your VU ID” in the First Octet (Left most) of the IP address, and then Identify the classes of the IP addresses after addition

here my id last 2 digit is 67 you add your own

 [ 130.168.10.40]         [67+ 130.168.10.40]   =  [ 197.168.10.40]    Class (B)
[10.120. 20. 0   ]      [67+10.120. 20. 0   ]  =  [ 77.120.20.0]           Class (A)

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